Base | Representation |
---|---|
bin | 11101111000011111001010… |
… | …100110111101011011101011 |
3 | 122020100010011102200001210021 |
4 | 131320133022212331123223 |
5 | 114211232102444013120 |
6 | 1143303505315501311 |
7 | 36453102403456261 |
oct | 3570371246753353 |
9 | 566303142601707 |
10 | 131425103501035 |
11 | 38970089754393 |
12 | 128a70952b7837 |
13 | 5844445c93786 |
14 | 246501a7b4431 |
15 | 102da06522aaa |
hex | 7787ca9bd6eb |
131425103501035 has 4 divisors (see below), whose sum is σ = 157710124201248. Its totient is φ = 105140082800824.
The previous prime is 131425103500973. The next prime is 131425103501051. The reversal of 131425103501035 is 530105301524131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131425103501035 - 219 = 131425102976747 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13142510350099 + ... + 13142510350108.
It is an arithmetic number, because the mean of its divisors is an integer number (39427531050312).
Almost surely, 2131425103501035 is an apocalyptic number.
131425103501035 is a deficient number, since it is larger than the sum of its proper divisors (26285020700213).
131425103501035 is an equidigital number, since it uses as much as digits as its factorization.
131425103501035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26285020700212.
The product of its (nonzero) digits is 27000, while the sum is 34.
The spelling of 131425103501035 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, one hundred three million, five hundred one thousand, thirty-five".
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