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1314251450023 = 4757494863941
BaseRepresentation
bin10011000111111111011…
…111011010011010100111
311122122022102222010101111
4103013333133122122213
5133013041332400043
62443431521405451
7163644243001351
oct23077737323247
94578272863344
101314251450023
11467409754566
12192864199887
1396c198359c5
14478781d80d1
15242c017709d
hex131ff7da6a7

1314251450023 has 8 divisors (see below), whose sum is σ = 1342447992000. Its totient is φ = 1286064647520.

The previous prime is 1314251449997. The next prime is 1314251450047. The reversal of 1314251450023 is 3200541524131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314251450023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314251450053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2161768 + ... + 2702173.

It is an arithmetic number, because the mean of its divisors is an integer number (167805999000).

Almost surely, 21314251450023 is an apocalyptic number.

1314251450023 is a deficient number, since it is larger than the sum of its proper divisors (28196541977).

1314251450023 is an equidigital number, since it uses as much as digits as its factorization.

1314251450023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4869737.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1314251450023 its reverse (3200541524131), we get a palindrome (4514792974154).

The spelling of 1314251450023 in words is "one trillion, three hundred fourteen billion, two hundred fifty-one million, four hundred fifty thousand, twenty-three".

Divisors: 1 47 5749 270203 4863941 228605227 27962796809 1314251450023