Base | Representation |
---|---|
bin | 11101111000011111011000… |
… | …001111100010111000101110 |
3 | 122020100010202101002102011110 |
4 | 131320133120033202320232 |
5 | 114211233040023302024 |
6 | 1143303544130332450 |
7 | 36453111151655364 |
oct | 3570373017427056 |
9 | 566303671072143 |
10 | 131425332244014 |
11 | 38970196889376 |
12 | 128a7139a2a126 |
13 | 58444814a2853 |
14 | 246503cd19634 |
15 | 102da1b658629 |
hex | 7787d83e2e2e |
131425332244014 has 8 divisors (see below), whose sum is σ = 262850664488040. Its totient is φ = 43808444081336.
The previous prime is 131425332243973. The next prime is 131425332244027. The reversal of 131425332244014 is 410442233524131.
It is a sphenic number, since it is the product of 3 distinct primes.
131425332244014 is an admirable number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10952111020329 + ... + 10952111020340.
It is an arithmetic number, because the mean of its divisors is an integer number (32856333061005).
Almost surely, 2131425332244014 is an apocalyptic number.
131425332244014 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131425332244014 is a wasteful number, since it uses less digits than its factorization.
131425332244014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21904222040674.
The product of its (nonzero) digits is 276480, while the sum is 39.
Adding to 131425332244014 its reverse (410442233524131), we get a palindrome (541867565768145).
The spelling of 131425332244014 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, three hundred thirty-two million, two hundred forty-four thousand, fourteen".
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