Base | Representation |
---|---|
bin | 11101111000011111011001… |
… | …010111000111010101101011 |
3 | 122020100010210200101121011001 |
4 | 131320133121113013111223 |
5 | 114211233104324134142 |
6 | 1143303550040415431 |
7 | 36453111500305624 |
oct | 3570373127072553 |
9 | 566303720347131 |
10 | 131425351005547 |
11 | 389701a6433175 |
12 | 128a7144177577 |
13 | 5844485341351 |
14 | 2465041600a4b |
15 | 102da1d1125b7 |
hex | 7787d95c756b |
131425351005547 has 2 divisors, whose sum is σ = 131425351005548. Its totient is φ = 131425351005546.
The previous prime is 131425351005517. The next prime is 131425351005569. The reversal of 131425351005547 is 745500153524131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131425351005547 - 27 = 131425351005419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131425351005497 and 131425351005506.
It is not a weakly prime, because it can be changed into another prime (131425351005517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712675502773 + 65712675502774.
It is an arithmetic number, because the mean of its divisors is an integer number (65712675502774).
Almost surely, 2131425351005547 is an apocalyptic number.
131425351005547 is a deficient number, since it is larger than the sum of its proper divisors (1).
131425351005547 is an equidigital number, since it uses as much as digits as its factorization.
131425351005547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260000, while the sum is 46.
The spelling of 131425351005547 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, three hundred fifty-one million, five thousand, five hundred forty-seven".
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