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131425351005517 is a prime number
BaseRepresentation
bin11101111000011111011001…
…010111000111010101001101
3122020100010210200101121002221
4131320133121113013111031
5114211233104324134032
61143303550040415341
736453111500305552
oct3570373127072515
9566303720347087
10131425351005517
11389701a6433148
12128a7144177551
13584448534132a
142465041600a29
15102da1d112597
hex7787d95c754d

131425351005517 has 2 divisors, whose sum is σ = 131425351005518. Its totient is φ = 131425351005516.

The previous prime is 131425351005463. The next prime is 131425351005547. The reversal of 131425351005517 is 715500153524131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89377246234116 + 42048104771401 = 9453954^2 + 6484451^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131425351005517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131425351005547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712675502758 + 65712675502759.

It is an arithmetic number, because the mean of its divisors is an integer number (65712675502759).

Almost surely, 2131425351005517 is an apocalyptic number.

It is an amenable number.

131425351005517 is a deficient number, since it is larger than the sum of its proper divisors (1).

131425351005517 is an equidigital number, since it uses as much as digits as its factorization.

131425351005517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 315000, while the sum is 43.

The spelling of 131425351005517 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, three hundred fifty-one million, five thousand, five hundred seventeen".