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131425514334533 is a prime number
BaseRepresentation
bin11101111000011111100011…
…000110001010100101000101
3122020100011020001201120101202
4131320133203012022211011
5114211233423132201113
61143304014153232245
736453115522501466
oct3570374306124505
9566304201646352
10131425514334533
113897027a649701
12128a718aa02685
1358444b0129113
142465059198d6d
15102da2c626258
hex7787e318a945

131425514334533 has 2 divisors, whose sum is σ = 131425514334534. Its totient is φ = 131425514334532.

The previous prime is 131425514334523. The next prime is 131425514334553. The reversal of 131425514334533 is 335433415524131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107365096294369 + 24060418040164 = 10361713^2 + 4905142^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131425514334533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131425514334523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712757167266 + 65712757167267.

It is an arithmetic number, because the mean of its divisors is an integer number (65712757167267).

Almost surely, 2131425514334533 is an apocalyptic number.

It is an amenable number.

131425514334533 is a deficient number, since it is larger than the sum of its proper divisors (1).

131425514334533 is an equidigital number, since it uses as much as digits as its factorization.

131425514334533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888000, while the sum is 47.

Adding to 131425514334533 its reverse (335433415524131), we get a palindrome (466858929858664).

The spelling of 131425514334533 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, five hundred fourteen million, three hundred thirty-four thousand, five hundred thirty-three".