Base | Representation |
---|---|
bin | 11101111000011111100011… |
… | …000110001010100101000101 |
3 | 122020100011020001201120101202 |
4 | 131320133203012022211011 |
5 | 114211233423132201113 |
6 | 1143304014153232245 |
7 | 36453115522501466 |
oct | 3570374306124505 |
9 | 566304201646352 |
10 | 131425514334533 |
11 | 3897027a649701 |
12 | 128a718aa02685 |
13 | 58444b0129113 |
14 | 2465059198d6d |
15 | 102da2c626258 |
hex | 7787e318a945 |
131425514334533 has 2 divisors, whose sum is σ = 131425514334534. Its totient is φ = 131425514334532.
The previous prime is 131425514334523. The next prime is 131425514334553. The reversal of 131425514334533 is 335433415524131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107365096294369 + 24060418040164 = 10361713^2 + 4905142^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131425514334533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131425514334523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712757167266 + 65712757167267.
It is an arithmetic number, because the mean of its divisors is an integer number (65712757167267).
Almost surely, 2131425514334533 is an apocalyptic number.
It is an amenable number.
131425514334533 is a deficient number, since it is larger than the sum of its proper divisors (1).
131425514334533 is an equidigital number, since it uses as much as digits as its factorization.
131425514334533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3888000, while the sum is 47.
Adding to 131425514334533 its reverse (335433415524131), we get a palindrome (466858929858664).
The spelling of 131425514334533 in words is "one hundred thirty-one trillion, four hundred twenty-five billion, five hundred fourteen million, three hundred thirty-four thousand, five hundred thirty-three".
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