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131431102020047 is a prime number
BaseRepresentation
bin11101111000100100110000…
…001001011111100111001111
3122020100200122110221101221002
4131320210300021133213033
5114211331344104120142
61143310340440530515
736453404142156014
oct3570446011374717
9566320573841832
10131431102020047
1138972687763515
12128a828a180a3b
135844b909613cb
14246542931970b
15102dc57e66a32
hex77893025f9cf

131431102020047 has 2 divisors, whose sum is σ = 131431102020048. Its totient is φ = 131431102020046.

The previous prime is 131431102020017. The next prime is 131431102020067. The reversal of 131431102020047 is 740020201134131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131431102020047 - 218 = 131431101757903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131431102020017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65715551010023 + 65715551010024.

It is an arithmetic number, because the mean of its divisors is an integer number (65715551010024).

Almost surely, 2131431102020047 is an apocalyptic number.

131431102020047 is a deficient number, since it is larger than the sum of its proper divisors (1).

131431102020047 is an equidigital number, since it uses as much as digits as its factorization.

131431102020047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 131431102020047 its reverse (740020201134131), we get a palindrome (871451303154178).

The spelling of 131431102020047 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, one hundred two million, twenty thousand, forty-seven".