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131431121402142 = 23191152904573703
BaseRepresentation
bin11101111000100100110001…
…010011011011100100011110
3122020100200200211102010011110
4131320210301103123210132
5114211331414034332032
61143310342412202450
736453404466002412
oct3570446123334436
9566320624363143
10131431121402142
11389726976a1581
12128a8294769426
135844b949894c3
14246542bb22d42
15102dc599e47cc
hex7789314db91e

131431121402142 has 16 divisors (see below), whose sum is σ = 276697097688960. Its totient is φ = 41504564653272.

The previous prime is 131431121402093. The next prime is 131431121402143. The reversal of 131431121402142 is 241204121134131.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131431121402143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 576452286738 + ... + 576452286965.

It is an arithmetic number, because the mean of its divisors is an integer number (17293568605560).

Almost surely, 2131431121402142 is an apocalyptic number.

131431121402142 is an abundant number, since it is smaller than the sum of its proper divisors (145265976286818).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131431121402142 is a wasteful number, since it uses less digits than its factorization.

131431121402142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1152904573727.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 131431121402142 its reverse (241204121134131), we get a palindrome (372635242536273).

The spelling of 131431121402142 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, one hundred twenty-one million, four hundred two thousand, one hundred forty-two".

Divisors: 1 2 3 6 19 38 57 114 1152904573703 2305809147406 3458713721109 6917427442218 21905186900357 43810373800714 65715560701071 131431121402142