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13143221210311 = 13892394607957
BaseRepresentation
bin1011111101000010010100…
…0010000000110011000111
31201112110221200110211212021
42333100211002000303013
53210314304112212221
643541525032104011
72524365162660403
oct277204502006307
951473850424767
1013143221210311
114208010803915
1215832b2235007
13744528a041ca
143361c73a0103
1517bd43096041
hexbf425080cc7

13143221210311 has 4 divisors (see below), whose sum is σ = 13143315957192. Its totient is φ = 13143126463432.

The previous prime is 13143221210279. The next prime is 13143221210321. The reversal of 13143221210311 is 11301212234131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13143221210311 - 25 = 13143221210279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13143221210321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47165056 + ... + 47442901.

It is an arithmetic number, because the mean of its divisors is an integer number (3285828989298).

Almost surely, 213143221210311 is an apocalyptic number.

13143221210311 is a deficient number, since it is larger than the sum of its proper divisors (94746881).

13143221210311 is an equidigital number, since it uses as much as digits as its factorization.

13143221210311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94746880.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 13143221210311 its reverse (11301212234131), we get a palindrome (24444433444442).

The spelling of 13143221210311 in words is "thirteen trillion, one hundred forty-three billion, two hundred twenty-one million, two hundred ten thousand, three hundred eleven".

Divisors: 1 138923 94607957 13143221210311