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13143303240313 = 43305658214891
BaseRepresentation
bin1011111101000010100111…
…1010111011101001111001
31201112111011101211101212111
42333100221322323221321
53210314441112142223
643541541122212321
72524400210140051
oct277205172735171
951474141741774
1013143303240313
114208053041204
1215833157b40a1
1374453c9c557c
143361d4234561
1517bd4a39b30d
hexbf429ebba79

13143303240313 has 4 divisors (see below), whose sum is σ = 13448961455248. Its totient is φ = 12837645025380.

The previous prime is 13143303240283. The next prime is 13143303240383. The reversal of 13143303240313 is 31304230334131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13143303240313 - 25 = 13143303240281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13143303240383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152829107403 + ... + 152829107488.

It is an arithmetic number, because the mean of its divisors is an integer number (3362240363812).

Almost surely, 213143303240313 is an apocalyptic number.

It is an amenable number.

13143303240313 is a deficient number, since it is larger than the sum of its proper divisors (305658214935).

13143303240313 is an equidigital number, since it uses as much as digits as its factorization.

13143303240313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305658214934.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13143303240313 its reverse (31304230334131), we get a palindrome (44447533574444).

The spelling of 13143303240313 in words is "thirteen trillion, one hundred forty-three billion, three hundred three million, two hundred forty thousand, three hundred thirteen".

Divisors: 1 43 305658214891 13143303240313