Base | Representation |
---|---|
bin | 1011111101000010100111… |
… | …1010111011101010111111 |
3 | 1201112111011101211101222002 |
4 | 2333100221322323222333 |
5 | 3210314441112143013 |
6 | 43541541122212515 |
7 | 2524400210140211 |
oct | 277205172735277 |
9 | 51474141741862 |
10 | 13143303240383 |
11 | 4208053041268 |
12 | 15833157b413b |
13 | 74453c9c5604 |
14 | 3361d42345b1 |
15 | 17bd4a39b358 |
hex | bf429ebbabf |
13143303240383 has 2 divisors, whose sum is σ = 13143303240384. Its totient is φ = 13143303240382.
The previous prime is 13143303240283. The next prime is 13143303240407. The reversal of 13143303240383 is 38304230334131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13143303240383 - 210 = 13143303239359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143303240283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571651620191 + 6571651620192.
It is an arithmetic number, because the mean of its divisors is an integer number (6571651620192).
Almost surely, 213143303240383 is an apocalyptic number.
13143303240383 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143303240383 is an equidigital number, since it uses as much as digits as its factorization.
13143303240383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 38.
The spelling of 13143303240383 in words is "thirteen trillion, one hundred forty-three billion, three hundred three million, two hundred forty thousand, three hundred eighty-three".
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