Base | Representation |
---|---|
bin | 111101001101000000… |
… | …1011111101010101110 |
3 | 110120020210120100222121 |
4 | 1322122001133222232 |
5 | 4123133333230443 |
6 | 140213551303154 |
7 | 12332014635202 |
oct | 1723201375256 |
9 | 416223510877 |
10 | 131433101998 |
11 | 50816617950 |
12 | 2158081aaba |
13 | c517a73193 |
14 | 650b956b02 |
15 | 3643a964ed |
hex | 1e9a05faae |
131433101998 has 32 divisors (see below), whose sum is σ = 215824435200. Its totient is φ = 59533584000.
The previous prime is 131433101993. The next prime is 131433102007. The reversal of 131433101998 is 899101334131.
131433101998 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131433101993) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27385203 + ... + 27390001.
It is an arithmetic number, because the mean of its divisors is an integer number (6744513600).
Almost surely, 2131433101998 is an apocalyptic number.
131433101998 is a deficient number, since it is larger than the sum of its proper divisors (84391333202).
131433101998 is a wasteful number, since it uses less digits than its factorization.
131433101998 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8904.
The product of its (nonzero) digits is 69984, while the sum is 43.
The spelling of 131433101998 in words is "one hundred thirty-one billion, four hundred thirty-three million, one hundred one thousand, nine hundred ninety-eight".
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