13143311354115 has 24 divisors (see below), whose sum is σ = 22812074945088. Its totient is φ = 7000432128000.

The previous prime is 13143311354113. The next prime is 13143311354161. The reversal of 13143311354115 is 51145311334131.

13143311354115 is a `hidden beast` number, since 1 + 31 + 43 + 31 + 1 + 3 + 541 + 15 = 666.

It is not a de Polignac number, because 13143311354115 - 2¹ = 13143311354113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13143311354115.

It is not an unprimeable number, because it can be changed into a prime (13143311354113) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 194422654 + ... + 194490243.

It is an arithmetic number, because the mean of its divisors is an integer number (950503122712).

Almost surely, 2^{13143311354115} is an apocalyptic number.

13143311354115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13143311354115 is a deficient number, since it is larger than the sum of its proper divisors (9668763590973).

13143311354115 is a wasteful number, since it uses less digits than its factorization.

13143311354115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 388913659 (or 388913656 counting only the distinct ones).

The product of its digits is 32400, while the sum is 36.

Adding to 13143311354115 its reverse (51145311334131), we get a palindrome (64288622688246).

The spelling of 13143311354115 in words is "thirteen trillion, one hundred forty-three billion, three hundred eleven million, three hundred fifty-four thousand, one hundred fifteen".