Base | Representation |
---|---|
bin | 11000011110110011… |
… | …11100111111010110 |
3 | 1020220222120001021022 |
4 | 30033121330333112 |
5 | 203404200113132 |
6 | 10012111521142 |
7 | 643463514101 |
oct | 141731747726 |
9 | 36828501238 |
10 | 13143363542 |
11 | 56350a4621 |
12 | 26698291b2 |
13 | 1315cb8cba |
14 | 8c9807738 |
15 | 51dd1ee12 |
hex | 30f67cfd6 |
13143363542 has 4 divisors (see below), whose sum is σ = 19715045316. Its totient is φ = 6571681770.
The previous prime is 13143363503. The next prime is 13143363581. The reversal of 13143363542 is 24536334131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13143363503) and next prime (13143363581).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285840884 + ... + 3285840887.
It is an arithmetic number, because the mean of its divisors is an integer number (4928761329).
Almost surely, 213143363542 is an apocalyptic number.
13143363542 is a deficient number, since it is larger than the sum of its proper divisors (6571681774).
13143363542 is an equidigital number, since it uses as much as digits as its factorization.
13143363542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6571681773.
The product of its digits is 77760, while the sum is 35.
Adding to 13143363542 its reverse (24536334131), we get a palindrome (37679697673).
The spelling of 13143363542 in words is "thirteen billion, one hundred forty-three million, three hundred sixty-three thousand, five hundred forty-two".
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