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131434113 = 344398897
BaseRepresentation
bin1111101010110…
…00011010000001
3100011022112201010
413311120122001
5232121342423
621013031133
73154112556
oct765303201
9304275633
10131434113
1168211438
12380254a9
13212cb485
1413654a2d
15b813693
hex7d58681

131434113 has 8 divisors (see below), whose sum is σ = 175642848. Its totient is φ = 87424064.

The previous prime is 131434111. The next prime is 131434129. The reversal of 131434113 is 311434131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131434113 - 21 = 131434111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131434113.

It is not an unprimeable number, because it can be changed into a prime (131434111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48120 + ... + 50777.

It is an arithmetic number, because the mean of its divisors is an integer number (21955356).

Almost surely, 2131434113 is an apocalyptic number.

It is an amenable number.

131434113 is a deficient number, since it is larger than the sum of its proper divisors (44208735).

131434113 is an equidigital number, since it uses as much as digits as its factorization.

131434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99343.

The product of its digits is 432, while the sum is 21.

The square root of 131434113 is about 11464.4717715209. The cubic root of 131434113 is about 508.4356950422.

Adding to 131434113 its reverse (311434131), we get a palindrome (442868244).

The spelling of 131434113 in words is "one hundred thirty-one million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 443 1329 98897 296691 43811371 131434113