Base | Representation |
---|---|
bin | 1011111101000011000001… |
… | …1001111010000011111111 |
3 | 1201112111102222112011102022 |
4 | 2333100300121322003333 |
5 | 3210320201434223201 |
6 | 43542000005550355 |
7 | 2524403000603255 |
oct | 277206031720377 |
9 | 51474388464368 |
10 | 13143412023551 |
11 | 42080a9491707 |
12 | 15833461153bb |
13 | 7445593c2b54 |
14 | 3362048705d5 |
15 | 17bd54bd841b |
hex | bf43067a0ff |
13143412023551 has 2 divisors, whose sum is σ = 13143412023552. Its totient is φ = 13143412023550.
The previous prime is 13143412023487. The next prime is 13143412023653. The reversal of 13143412023551 is 15532021434131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13143412023551 - 26 = 13143412023487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143412023151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571706011775 + 6571706011776.
It is an arithmetic number, because the mean of its divisors is an integer number (6571706011776).
Almost surely, 213143412023551 is an apocalyptic number.
13143412023551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143412023551 is an equidigital number, since it uses as much as digits as its factorization.
13143412023551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13143412023551 its reverse (15532021434131), we get a palindrome (28675433457682).
The spelling of 13143412023551 in words is "thirteen trillion, one hundred forty-three billion, four hundred twelve million, twenty-three thousand, five hundred fifty-one".
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