13143426001 has 2 divisors, whose sum is σ = 13143426002. Its totient is φ = 13143426000.

The previous prime is 13143425993. The next prime is 13143426011. The reversal of 13143426001 is 10062434131.

13143426001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8519290000 + 4624136001 = 92300^2 + 68001^2 .

It is an emirp because it is prime and its reverse (10062434131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13143426001 - 2³ = 13143425993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13143426011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571713000 + 6571713001.

It is an arithmetic number, because the mean of its divisors is an integer number (6571713001).

Almost surely, 2^13143426001 is an apocalyptic number.

It is an amenable number.

13143426001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143426001 is an equidigital number, since it uses as much as digits as its factorization.

13143426001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 13143426001 in words is "thirteen billion, one hundred forty-three million, four hundred twenty-six thousand, one".