13143451401141 has 4 divisors (see below), whose sum is σ = 17524601868192. Its totient is φ = 8762300934092.

The previous prime is 13143451401137. The next prime is 13143451401151. The reversal of 13143451401141 is 14110415434131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13143451401141 - 2² = 13143451401137 is a prime.

It is a super-2 number, since 2×13143451401141² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13143451401131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190575233521 + ... + 2190575233526.

It is an arithmetic number, because the mean of its divisors is an integer number (4381150467048).

Almost surely, 2^{13143451401141} is an apocalyptic number.

It is an amenable number.

13143451401141 is a deficient number, since it is larger than the sum of its proper divisors (4381150467051).

13143451401141 is an equidigital number, since it uses as much as digits as its factorization.

13143451401141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4381150467050.

The product of its (nonzero) digits is 11520, while the sum is 33.

Adding to 13143451401141 its reverse (14110415434131), we get a palindrome (27253866835272).

The spelling of 13143451401141 in words is "thirteen trillion, one hundred forty-three billion, four hundred fifty-one million, four hundred one thousand, one hundred forty-one".