13143545533 has 4 divisors (see below), whose sum is σ = 13154293728. Its totient is φ = 13132797340.

The previous prime is 13143545531. The next prime is 13143545539. The reversal of 13143545533 is 33554534131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13143545533 - 2¹ = 13143545531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13143545492 and 13143545501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13143545531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5372263 + ... + 5374708.

It is an arithmetic number, because the mean of its divisors is an integer number (3288573432).

Almost surely, 2^13143545533 is an apocalyptic number.

It is an amenable number.

13143545533 is a deficient number, since it is larger than the sum of its proper divisors (10748195).

13143545533 is a wasteful number, since it uses less digits than its factorization.

13143545533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10748194.

The product of its digits is 162000, while the sum is 37.

The spelling of 13143545533 in words is "thirteen billion, one hundred forty-three million, five hundred forty-five thousand, five hundred thirty-three".