Base | Representation |
---|---|
bin | 11101111000101001000010… |
… | …101010001000101100110011 |
3 | 122020101010112110000202112210 |
4 | 131320221002222020230303 |
5 | 114211420312112043011 |
6 | 1143312421441023203 |
7 | 36453626234325540 |
oct | 3570510252105463 |
9 | 566333473022483 |
10 | 131435707534131 |
11 | 38974630421400 |
12 | 128a9154624b03 |
13 | 5845445b5c480 |
14 | 2465744c4dbc7 |
15 | 102de274486a6 |
hex | 778a42a88b33 |
131435707534131 has 96 divisors (see below), whose sum is σ = 245255222983680. Its totient is φ = 60852798800640.
The previous prime is 131435707534121. The next prime is 131435707534133.
131435707534131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 131435707534131 - 27 = 131435707534003 is a prime.
It is a super-2 number, since 2×1314357075341312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131435707534133) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 67644135 + ... + 69560048.
It is an arithmetic number, because the mean of its divisors is an integer number (2554741906080).
Almost surely, 2131435707534131 is an apocalyptic number.
131435707534131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131435707534131 is a deficient number, since it is larger than the sum of its proper divisors (113819515449549).
131435707534131 is a wasteful number, since it uses less digits than its factorization.
131435707534131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137204257 (or 137204246 counting only the distinct ones).
The product of its (nonzero) digits is 1587600, while the sum is 48.
The spelling of 131435707534131 in words is "one hundred thirty-one trillion, four hundred thirty-five billion, seven hundred seven million, five hundred thirty-four thousand, one hundred thirty-one".
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