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1314369060161 is a prime number
BaseRepresentation
bin10011001000000110100…
…000000011110101000001
311122122121122021100011112
4103020012200003311001
5133013311434411121
62443451322253105
7163650201450143
oct23100640036501
94578548240145
101314369060161
1146746a083823
12192897657195
1396c38003bc1
1447889a90c93
15242ca65975b
hex13206803d41

1314369060161 has 2 divisors, whose sum is σ = 1314369060162. Its totient is φ = 1314369060160.

The previous prime is 1314369060133. The next prime is 1314369060163. The reversal of 1314369060161 is 1610609634131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 710554587136 + 603814473025 = 842944^2 + 777055^2 .

It is an emirp because it is prime and its reverse (1610609634131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314369060161 - 234 = 1297189190977 is a prime.

Together with 1314369060163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1314369060163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657184530080 + 657184530081.

It is an arithmetic number, because the mean of its divisors is an integer number (657184530081).

Almost surely, 21314369060161 is an apocalyptic number.

It is an amenable number.

1314369060161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314369060161 is an equidigital number, since it uses as much as digits as its factorization.

1314369060161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 1314369060161 in words is "one trillion, three hundred fourteen billion, three hundred sixty-nine million, sixty thousand, one hundred sixty-one".