131440021301041 has 2 divisors, whose sum is σ = 131440021301042. Its totient is φ = 131440021301040.

The previous prime is 131440021300963. The next prime is 131440021301063. The reversal of 131440021301041 is 140103120044131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65821921051041 + 65618100250000 = 8113071^2 + 8100500^2 .

It is a cyclic number.

It is not a de Polignac number, because 131440021301041 - 2³⁷ = 131302582347569 is a prime.

It is a super-2 number, since 2×131440021301041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131440021300997 and 131440021301015.

It is not a weakly prime, because it can be changed into another prime (131440021301341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720010650520 + 65720010650521.

It is an arithmetic number, because the mean of its divisors is an integer number (65720010650521).

Almost surely, 2^{131440021301041} is an apocalyptic number.

It is an amenable number.

131440021301041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131440021301041 is an equidigital number, since it uses as much as digits as its factorization.

131440021301041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131440021301041 its reverse (140103120044131), we get a palindrome (271543141345172).

The spelling of 131440021301041 in words is "one hundred thirty-one trillion, four hundred forty billion, twenty-one million, three hundred one thousand, forty-one".