Base | Representation |
---|---|
bin | 11101111000101101000011… |
… | …110001110110011011100011 |
3 | 122020101112200002010211011201 |
4 | 131320231003301312123203 |
5 | 114212003130423112323 |
6 | 1143314413500022031 |
7 | 36454141154620324 |
oct | 3570550361663343 |
9 | 566345602124151 |
10 | 131440021300963 |
11 | 38976444432261 |
12 | 128a9b59231917 |
13 | 584598278bc1b |
14 | 2465a33b1c44b |
15 | 102e0caeeb8ad |
hex | 778b43c766e3 |
131440021300963 has 2 divisors, whose sum is σ = 131440021300964. Its totient is φ = 131440021300962.
The previous prime is 131440021300961. The next prime is 131440021301041. The reversal of 131440021300963 is 369003120044131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131440021300963 - 21 = 131440021300961 is a prime.
Together with 131440021300961, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131440021300961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720010650481 + 65720010650482.
It is an arithmetic number, because the mean of its divisors is an integer number (65720010650482).
Almost surely, 2131440021300963 is an apocalyptic number.
131440021300963 is a deficient number, since it is larger than the sum of its proper divisors (1).
131440021300963 is an equidigital number, since it uses as much as digits as its factorization.
131440021300963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 131440021300963 in words is "one hundred thirty-one trillion, four hundred forty billion, twenty-one million, three hundred thousand, nine hundred sixty-three".
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