Base | Representation |
---|---|
bin | 111101001101010000… |
… | …0100011010110001101 |
3 | 110120021100220000001221 |
4 | 1322122200203112031 |
5 | 4123142424243113 |
6 | 140214442003341 |
7 | 12332144064355 |
oct | 1723240432615 |
9 | 416240800057 |
10 | 131441243533 |
11 | 50820178796 |
12 | 215834a6551 |
13 | c519663b62 |
14 | 650ca75b65 |
15 | 364465398d |
hex | 1e9a82358d |
131441243533 has 4 divisors (see below), whose sum is σ = 133669061280. Its totient is φ = 129213425788.
The previous prime is 131441243519. The next prime is 131441243573. The reversal of 131441243533 is 335342144131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131441243533 - 217 = 131441112461 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131441243573) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1113908785 + ... + 1113908902.
It is an arithmetic number, because the mean of its divisors is an integer number (33417265320).
Almost surely, 2131441243533 is an apocalyptic number.
It is an amenable number.
131441243533 is a deficient number, since it is larger than the sum of its proper divisors (2227817747).
131441243533 is an equidigital number, since it uses as much as digits as its factorization.
131441243533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2227817746.
The product of its digits is 51840, while the sum is 34.
Adding to 131441243533 its reverse (335342144131), we get a palindrome (466783387664).
The spelling of 131441243533 in words is "one hundred thirty-one billion, four hundred forty-one million, two hundred forty-three thousand, five hundred thirty-three".
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