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13144205839697 is a prime number
BaseRepresentation
bin1011111101000101111110…
…1110000100110101010001
31201112120111022020012110022
42333101133232010311101
53210323313143332242
643542210444113225
72524431450123122
oct277213756046521
951476438205408
1013144205839697
114208476589509
121583527b35815
137446549bc14a
1433627c06a049
1517bd9e73d0d2
hexbf45fb84d51

13144205839697 has 2 divisors, whose sum is σ = 13144205839698. Its totient is φ = 13144205839696.

The previous prime is 13144205839691. The next prime is 13144205839727. The reversal of 13144205839697 is 79693850244131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9525673604161 + 3618532235536 = 3086369^2 + 1902244^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13144205839697 is a prime.

It is a super-2 number, since 2×131442058396972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13144205839691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572102919848 + 6572102919849.

It is an arithmetic number, because the mean of its divisors is an integer number (6572102919849).

It is a 1-persistent number, because it is pandigital, but 2⋅13144205839697 = 26288411679394 is not.

Almost surely, 213144205839697 is an apocalyptic number.

It is an amenable number.

13144205839697 is a deficient number, since it is larger than the sum of its proper divisors (1).

13144205839697 is an equidigital number, since it uses as much as digits as its factorization.

13144205839697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39191040, while the sum is 62.

The spelling of 13144205839697 in words is "thirteen trillion, one hundred forty-four billion, two hundred five million, eight hundred thirty-nine thousand, six hundred ninety-seven".