13144210034001 has 4 divisors (see below), whose sum is σ = 17525613378672. Its totient is φ = 8762806689332.

The previous prime is 13144210033987. The next prime is 13144210034023. The reversal of 13144210034001 is 10043001244131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13144210034001 - 2²² = 13144205839697 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13144210034801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190701672331 + ... + 2190701672336.

It is an arithmetic number, because the mean of its divisors is an integer number (4381403344668).

Almost surely, 2^{13144210034001} is an apocalyptic number.

It is an amenable number.

13144210034001 is a deficient number, since it is larger than the sum of its proper divisors (4381403344671).

13144210034001 is an equidigital number, since it uses as much as digits as its factorization.

13144210034001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4381403344670.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13144210034001 its reverse (10043001244131), we get a palindrome (23187211278132).

The spelling of 13144210034001 in words is "thirteen trillion, one hundred forty-four billion, two hundred ten million, thirty-four thousand, one".