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131443000103 = 1939171766161
BaseRepresentation
bin111101001101010011…
…1010000001100100111
3110120021111012020122002
41322122213100030213
54123143402000403
6140214543355515
712332165031512
oct1723247201447
9416244166562
10131443000103
11508211684a8
1221583bb2b9b
13c519b2a54c
14650cdb1d79
15364489e188
hex1e9a9d0327

131443000103 has 8 divisors (see below), whose sum is σ = 138396454320. Its totient is φ = 124493086080.

The previous prime is 131443000097. The next prime is 131443000123. The reversal of 131443000103 is 301000344131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131443000103 - 212 = 131442996007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131443000123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 808658 + ... + 957503.

It is an arithmetic number, because the mean of its divisors is an integer number (17299556790).

Almost surely, 2131443000103 is an apocalyptic number.

131443000103 is a deficient number, since it is larger than the sum of its proper divisors (6953454217).

131443000103 is a wasteful number, since it uses less digits than its factorization.

131443000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1770097.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131443000103 its reverse (301000344131), we get a palindrome (432443344234).

The spelling of 131443000103 in words is "one hundred thirty-one billion, four hundred forty-three million, one hundred three", and thus it is an aban number.

Divisors: 1 19 3917 74423 1766161 33557059 6918052637 131443000103