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1314430423413 = 3438143474471
BaseRepresentation
bin10011001000001010001…
…010001001000101110101
311122122202220201220201120
4103020022022021011311
5133013423142022123
62443501353414153
7163651545152562
oct23101212110565
94578686656646
101314430423413
114674a0785958
121928b410a359
1396c4793a513
1447893ca5869
15242d0c2b2e3
hex1320a289175

1314430423413 has 4 divisors (see below), whose sum is σ = 1752573897888. Its totient is φ = 876286948940.

The previous prime is 1314430423409. The next prime is 1314430423447. The reversal of 1314430423413 is 3143240344131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1314430423413 - 22 = 1314430423409 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314430423483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219071737233 + ... + 219071737238.

It is an arithmetic number, because the mean of its divisors is an integer number (438143474472).

Almost surely, 21314430423413 is an apocalyptic number.

It is an amenable number.

1314430423413 is a deficient number, since it is larger than the sum of its proper divisors (438143474475).

1314430423413 is an equidigital number, since it uses as much as digits as its factorization.

1314430423413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438143474474.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1314430423413 its reverse (3143240344131), we get a palindrome (4457670767544).

The spelling of 1314430423413 in words is "one trillion, three hundred fourteen billion, four hundred thirty million, four hundred twenty-three thousand, four hundred thirteen".

Divisors: 1 3 438143474471 1314430423413