131443104614141 has 2 divisors, whose sum is σ = 131443104614142. Its totient is φ = 131443104614140.

The previous prime is 131443104614113. The next prime is 131443104614149. The reversal of 131443104614141 is 141416401344131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88626314364025 + 42816790250116 = 9414155^2 + 6543454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131443104614141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131443104614095 and 131443104614104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131443104614149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65721552307070 + 65721552307071.

It is an arithmetic number, because the mean of its divisors is an integer number (65721552307071).

Almost surely, 2^{131443104614141} is an apocalyptic number.

It is an amenable number.

131443104614141 is a deficient number, since it is larger than the sum of its proper divisors (1).

131443104614141 is an equidigital number, since it uses as much as digits as its factorization.

131443104614141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 38.

Adding to 131443104614141 its reverse (141416401344131), we get a palindrome (272859505958272).

The spelling of 131443104614141 in words is "one hundred thirty-one trillion, four hundred forty-three billion, one hundred four million, six hundred fourteen thousand, one hundred forty-one".