1314432334049 has 2 divisors, whose sum is σ = 1314432334050. Its totient is φ = 1314432334048.

The previous prime is 1314432334009. The next prime is 1314432334057. The reversal of 1314432334049 is 9404332344131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1047003725824 + 267428608225 = 1023232^2 + 517135^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314432334049 - 2³² = 1310137366753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1314432333997 and 1314432334015.

It is not a weakly prime, because it can be changed into another prime (1314432334009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657216167024 + 657216167025.

It is an arithmetic number, because the mean of its divisors is an integer number (657216167025).

Almost surely, 2^{1314432334049} is an apocalyptic number.

It is an amenable number.

1314432334049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314432334049 is an equidigital number, since it uses as much as digits as its factorization.

1314432334049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 41.

The spelling of 1314432334049 in words is "one trillion, three hundred fourteen billion, four hundred thirty-two million, three hundred thirty-four thousand, forty-nine".