Base | Representation |
---|---|
bin | 10011001000001010011… |
… | …000010000011001000011 |
3 | 11122122210011200220001120 |
4 | 103020022120100121003 |
5 | 133013430113421311 |
6 | 2443502005003323 |
7 | 163651621462530 |
oct | 23101230203103 |
9 | 4578704626046 |
10 | 1314434123331 |
11 | 4674a288273a |
12 | 1928b53b3543 |
13 | 96c48634614 |
14 | 47894589d87 |
15 | 242d120c706 |
hex | 1320a610643 |
1314434123331 has 24 divisors (see below), whose sum is σ = 2007042596352. Its totient is φ = 749572580400.
The previous prime is 1314434123291. The next prime is 1314434123333. The reversal of 1314434123331 is 1333214344131.
It is not a de Polignac number, because 1314434123331 - 223 = 1314425734723 is a prime.
It is a super-2 number, since 2×13144341233312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1314434123292 and 1314434123301.
It is not an unprimeable number, because it can be changed into a prime (1314434123333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4932886 + ... + 5192516.
It is an arithmetic number, because the mean of its divisors is an integer number (83626774848).
Almost surely, 21314434123331 is an apocalyptic number.
1314434123331 is a deficient number, since it is larger than the sum of its proper divisors (692608473021).
1314434123331 is an frugal number, since it uses more digits than its factorization.
1314434123331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260623 (or 260132 counting only the distinct ones).
The product of its digits is 31104, while the sum is 33.
Adding to 1314434123331 its reverse (1333214344131), we get a palindrome (2647648467462).
The spelling of 1314434123331 in words is "one trillion, three hundred fourteen billion, four hundred thirty-four million, one hundred twenty-three thousand, three hundred thirty-one".
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