131443434113 has 4 divisors (see below), whose sum is σ = 131447401428. Its totient is φ = 131439466800.

The previous prime is 131443434047. The next prime is 131443434209. The reversal of 131443434113 is 311434344131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311434344131 = 67 ⋅4648273793.

It can be written as a sum of positive squares in 2 ways, for example, as 60470744464 + 70972689649 = 245908^2 + 266407^2 .

It is a cyclic number.

It is not a de Polignac number, because 131443434113 - 2¹² = 131443430017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131443434113.

It is not an unprimeable number, because it can be changed into a prime (131443434613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1933538 + ... + 2000363.

It is an arithmetic number, because the mean of its divisors is an integer number (32861850357).

Almost surely, 2^131443434113 is an apocalyptic number.

It is an amenable number.

131443434113 is a deficient number, since it is larger than the sum of its proper divisors (3967315).

131443434113 is an equidigital number, since it uses as much as digits as its factorization.

131443434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3967314.

The product of its digits is 20736, while the sum is 32.

Adding to 131443434113 its reverse (311434344131), we get a palindrome (442877778244).

The spelling of 131443434113 in words is "one hundred thirty-one billion, four hundred forty-three million, four hundred thirty-four thousand, one hundred thirteen".