131452015111 has 4 divisors (see below), whose sum is σ = 131453023912. Its totient is φ = 131451006312.

The previous prime is 131452015081. The next prime is 131452015117. The reversal of 131452015111 is 111510254131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131452015111 - 2²¹ = 131449917959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131452015117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273801 + ... + 581266.

It is an arithmetic number, because the mean of its divisors is an integer number (32863255978).

Almost surely, 2^131452015111 is an apocalyptic number.

131452015111 is a deficient number, since it is larger than the sum of its proper divisors (1008801).

131452015111 is an equidigital number, since it uses as much as digits as its factorization.

131452015111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008800.

The product of its (nonzero) digits is 600, while the sum is 25.

Adding to 131452015111 its reverse (111510254131), we get a palindrome (242962269242).

The spelling of 131452015111 in words is "one hundred thirty-one billion, four hundred fifty-two million, fifteen thousand, one hundred eleven".