1314628487547 has 4 divisors (see below), whose sum is σ = 1752837983400. Its totient is φ = 876418991696.

The previous prime is 1314628487537. The next prime is 1314628487593. The reversal of 1314628487547 is 7457848264131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314628487547 - 2¹⁸ = 1314628225403 is a prime.

It is a super-2 number, since 2×1314628487547² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1314628487537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219104747922 + ... + 219104747927.

It is an arithmetic number, because the mean of its divisors is an integer number (438209495850).

Almost surely, 2^{1314628487547} is an apocalyptic number.

1314628487547 is a deficient number, since it is larger than the sum of its proper divisors (438209495853).

1314628487547 is an equidigital number, since it uses as much as digits as its factorization.

1314628487547 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438209495852.

The product of its digits is 36126720, while the sum is 60.

The spelling of 1314628487547 in words is "one trillion, three hundred fourteen billion, six hundred twenty-eight million, four hundred eighty-seven thousand, five hundred forty-seven".