Base | Representation |
---|---|
bin | 1011111101010001011101… |
… | …1001111000000001100111 |
3 | 1201112212110002000102010211 |
4 | 2333110113121320001213 |
5 | 3210401121103131403 |
6 | 43543440332000251 |
7 | 2524601020213315 |
oct | 277242731700147 |
9 | 51485402012124 |
10 | 13147287552103 |
11 | 420980808a671 |
12 | 1584048000087 |
13 | 744a262b3303 |
14 | 3364914630b5 |
15 | 17bed007306d |
hex | bf517678067 |
13147287552103 has 2 divisors, whose sum is σ = 13147287552104. Its totient is φ = 13147287552102.
The previous prime is 13147287551987. The next prime is 13147287552107. The reversal of 13147287552103 is 30125578274131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13147287552103 - 225 = 13147253997671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13147287552107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6573643776051 + 6573643776052.
It is an arithmetic number, because the mean of its divisors is an integer number (6573643776052).
Almost surely, 213147287552103 is an apocalyptic number.
13147287552103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13147287552103 is an equidigital number, since it uses as much as digits as its factorization.
13147287552103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1411200, while the sum is 49.
The spelling of 13147287552103 in words is "thirteen trillion, one hundred forty-seven billion, two hundred eighty-seven million, five hundred fifty-two thousand, one hundred three".
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