Base | Representation |
---|---|
bin | 1011111101010001100001… |
… | …0010110010000000000000 |
3 | 1201112212111010002022010220 |
4 | 2333110120102302000000 |
5 | 3210401133413012012 |
6 | 43543442023423040 |
7 | 2524601261053542 |
oct | 277243022620000 |
9 | 51485433068126 |
10 | 13147302469632 |
11 | 4209815549401 |
12 | 1584050bb4a80 |
13 | 744a29407256 |
14 | 336493427692 |
15 | 17bed151d08c |
hex | bf5184b2000 |
13147302469632 has 112 divisors (see below), whose sum is σ = 35872623098400. Its totient is φ = 4280516739072.
The previous prime is 13147302469621. The next prime is 13147302469699. The reversal of 13147302469632 is 23696420374131.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5163757 + ... + 7277292.
Almost surely, 213147302469632 is an apocalyptic number.
13147302469632 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13147302469632 is an abundant number, since it is smaller than the sum of its proper divisors (22725320628768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13147302469632 is an equidigital number, since it uses as much as digits as its factorization.
13147302469632 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12441121 (or 12441097 counting only the distinct ones).
The product of its (nonzero) digits is 3919104, while the sum is 51.
The spelling of 13147302469632 in words is "thirteen trillion, one hundred forty-seven billion, three hundred two million, four hundred sixty-nine thousand, six hundred thirty-two".
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