Base | Representation |
---|---|
bin | 111101001110100110… |
… | …0110010000011000101 |
3 | 110120101111211210211112 |
4 | 1322131030302003011 |
5 | 4123241004030032 |
6 | 140223133414405 |
7 | 12333232616144 |
oct | 1723514620305 |
9 | 416344753745 |
10 | 131486392517 |
11 | 508437058a7 |
12 | 2159663a405 |
13 | c525b1122c |
14 | 6514a6975b |
15 | 36485c11b2 |
hex | 1e9d3320c5 |
131486392517 has 2 divisors, whose sum is σ = 131486392518. Its totient is φ = 131486392516.
The previous prime is 131486392489. The next prime is 131486392529. The reversal of 131486392517 is 715293684131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128469197476 + 3017195041 = 358426^2 + 54929^2 .
It is a cyclic number.
It is not a de Polignac number, because 131486392517 - 210 = 131486391493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131486392537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65743196258 + 65743196259.
It is an arithmetic number, because the mean of its divisors is an integer number (65743196259).
Almost surely, 2131486392517 is an apocalyptic number.
It is an amenable number.
131486392517 is a deficient number, since it is larger than the sum of its proper divisors (1).
131486392517 is an equidigital number, since it uses as much as digits as its factorization.
131486392517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1088640, while the sum is 50.
The spelling of 131486392517 in words is "one hundred thirty-one billion, four hundred eighty-six million, three hundred ninety-two thousand, five hundred seventeen".
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