Base | Representation |
---|---|
bin | 11101111001100110000011… |
… | …110011101001000011000100 |
3 | 122020121101122110210122012201 |
4 | 131321212003303221003010 |
5 | 114214004002103220104 |
6 | 1143402455004524244 |
7 | 36461435642135302 |
oct | 3571460363510304 |
9 | 566541573718181 |
10 | 131501225054404 |
11 | 3899a3a134a077 |
12 | 128b999a250684 |
13 | 584b687725b4a |
14 | 246899c3db272 |
15 | 10309ae27c0a4 |
hex | 779983ce90c4 |
131501225054404 has 48 divisors (see below), whose sum is σ = 242783354419200. Its totient is φ = 62230568508416.
The previous prime is 131501225054401. The next prime is 131501225054417. The reversal of 131501225054404 is 404450522105131.
It is not an unprimeable number, because it can be changed into a prime (131501225054401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24799492 + ... + 29631355.
It is an arithmetic number, because the mean of its divisors is an integer number (5057986550400).
Almost surely, 2131501225054404 is an apocalyptic number.
It is an amenable number.
131501225054404 is a deficient number, since it is larger than the sum of its proper divisors (111282129364796).
131501225054404 is a wasteful number, since it uses less digits than its factorization.
131501225054404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54431292 (or 54431290 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 131501225054404 its reverse (404450522105131), we get a palindrome (535951747159535).
The spelling of 131501225054404 in words is "one hundred thirty-one trillion, five hundred one billion, two hundred twenty-five million, fifty-four thousand, four hundred four".
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