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131501345251993 is a prime number
BaseRepresentation
bin11101111001100110001010…
…111110001010001010011001
3122020121101221211222022022021
4131321212022332022022121
5114214004223341030433
61143402514541054441
736461441631611503
oct3571461276121231
9566541854868267
10131501345251993
113899a453186322
12128b9a12557421
13584b6a65bb992
1424689b0368d73
1510309b9ac122d
hex77998af8a299

131501345251993 has 2 divisors, whose sum is σ = 131501345251994. Its totient is φ = 131501345251992.

The previous prime is 131501345251891. The next prime is 131501345252161. The reversal of 131501345251993 is 399152543105131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117448653541129 + 14052691710864 = 10837373^2 + 3748692^2 .

It is a cyclic number.

It is not a de Polignac number, because 131501345251993 - 217 = 131501345120921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131501345251993.

It is not a weakly prime, because it can be changed into another prime (131501345255993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65750672625996 + 65750672625997.

It is an arithmetic number, because the mean of its divisors is an integer number (65750672625997).

Almost surely, 2131501345251993 is an apocalyptic number.

It is an amenable number.

131501345251993 is a deficient number, since it is larger than the sum of its proper divisors (1).

131501345251993 is an equidigital number, since it uses as much as digits as its factorization.

131501345251993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187000, while the sum is 52.

The spelling of 131501345251993 in words is "one hundred thirty-one trillion, five hundred one billion, three hundred forty-five million, two hundred fifty-one thousand, nine hundred ninety-three".