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131501345252161 is a prime number
BaseRepresentation
bin11101111001100110001010…
…111110001010001101000001
3122020121101221211222022112111
4131321212022332022031001
5114214004223341032121
61143402514541055321
736461441631612133
oct3571461276121501
9566541854868474
10131501345252161
113899a453186465
12128b9a12557541
13584b6a65bba91
1424689b0369053
1510309b9ac12e1
hex77998af8a341

131501345252161 has 2 divisors, whose sum is σ = 131501345252162. Its totient is φ = 131501345252160.

The previous prime is 131501345251993. The next prime is 131501345252197. The reversal of 131501345252161 is 161252543105131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99946387187761 + 31554958064400 = 9997319^2 + 5617380^2 .

It is a cyclic number.

It is not a de Polignac number, because 131501345252161 - 211 = 131501345250113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131501345282161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65750672626080 + 65750672626081.

It is an arithmetic number, because the mean of its divisors is an integer number (65750672626081).

Almost surely, 2131501345252161 is an apocalyptic number.

It is an amenable number.

131501345252161 is a deficient number, since it is larger than the sum of its proper divisors (1).

131501345252161 is an equidigital number, since it uses as much as digits as its factorization.

131501345252161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 40.

Adding to 131501345252161 its reverse (161252543105131), we get a palindrome (292753888357292).

The spelling of 131501345252161 in words is "one hundred thirty-one trillion, five hundred one billion, three hundred forty-five million, two hundred fifty-two thousand, one hundred sixty-one".