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13150261795063 is a prime number
BaseRepresentation
bin1011111101011100100010…
…1011101101100011110111
31201120011010100120121110111
42333113020223231203313
53210423214004420223
643545051420203451
72525034513651511
oct277271053554367
951504110517414
1013150261795063
11420aaa3a583a8
121584738099587
137450ab549ba3
14336694482bb1
1517c10622a30d
hexbf5c8aed8f7

13150261795063 has 2 divisors, whose sum is σ = 13150261795064. Its totient is φ = 13150261795062.

The previous prime is 13150261795049. The next prime is 13150261795163. The reversal of 13150261795063 is 36059716205131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13150261795063 is a prime.

It is a super-2 number, since 2×131502617950632 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13150261794998 and 13150261795016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13150261795043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6575130897531 + 6575130897532.

It is an arithmetic number, because the mean of its divisors is an integer number (6575130897532).

Almost surely, 213150261795063 is an apocalyptic number.

13150261795063 is a deficient number, since it is larger than the sum of its proper divisors (1).

13150261795063 is an equidigital number, since it uses as much as digits as its factorization.

13150261795063 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1020600, while the sum is 49.

The spelling of 13150261795063 in words is "thirteen trillion, one hundred fifty billion, two hundred sixty-one million, seven hundred ninety-five thousand, sixty-three".