Base | Representation |
---|---|
bin | 1011111101011100101001… |
… | …1011001110001110010111 |
3 | 1201120011012101120201220212 |
4 | 2333113022123032032113 |
5 | 3210423244000324324 |
6 | 43545054342520035 |
7 | 2525035320300401 |
oct | 277271233161627 |
9 | 51504171521825 |
10 | 13150291026839 |
11 | 421000950369a |
12 | 1584745a3601b |
13 | 7450b46132b5 |
14 | 3366982d1b71 |
15 | 17c108aa170e |
hex | bf5ca6ce397 |
13150291026839 has 2 divisors, whose sum is σ = 13150291026840. Its totient is φ = 13150291026838.
The previous prime is 13150291026823. The next prime is 13150291026907. The reversal of 13150291026839 is 93862019205131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13150291026839 - 24 = 13150291026823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13150291026139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6575145513419 + 6575145513420.
It is an arithmetic number, because the mean of its divisors is an integer number (6575145513420).
Almost surely, 213150291026839 is an apocalyptic number.
13150291026839 is a deficient number, since it is larger than the sum of its proper divisors (1).
13150291026839 is an equidigital number, since it uses as much as digits as its factorization.
13150291026839 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 699840, while the sum is 50.
Adding to 13150291026839 its sum of digits (50), we get a square (13150291026889 = 36263332).
The spelling of 13150291026839 in words is "thirteen trillion, one hundred fifty billion, two hundred ninety-one million, twenty-six thousand, eight hundred thirty-nine".
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