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131504023207 is a prime number
BaseRepresentation
bin111101001111001000…
…0000010011010100111
3110120102202000112121001
41322132100002122213
54123310012220312
6140225003334131
712333535516444
oct1723620023247
9416382015531
10131504023207
1150852658017
12215a0521347
13c5296750ab
1465171389cb
153649e05057
hex1e9e4026a7

131504023207 has 2 divisors, whose sum is σ = 131504023208. Its totient is φ = 131504023206.

The previous prime is 131504023177. The next prime is 131504023223. The reversal of 131504023207 is 702320405131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131504023207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131504023307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65752011603 + 65752011604.

It is an arithmetic number, because the mean of its divisors is an integer number (65752011604).

Almost surely, 2131504023207 is an apocalyptic number.

131504023207 is a deficient number, since it is larger than the sum of its proper divisors (1).

131504023207 is an equidigital number, since it uses as much as digits as its factorization.

131504023207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 28.

Adding to 131504023207 its reverse (702320405131), we get a palindrome (833824428338).

The spelling of 131504023207 in words is "one hundred thirty-one billion, five hundred four million, twenty-three thousand, two hundred seven".