Base | Representation |
---|---|
bin | 11101111001101010111111… |
… | …011011100110001011011100 |
3 | 122020121220022111211121011121 |
4 | 131321222333123212023130 |
5 | 114214100323202221302 |
6 | 1143405132245300324 |
7 | 36462014111334151 |
oct | 3571527733461334 |
9 | 566556274747147 |
10 | 131506520351452 |
11 | 389a1669409124 |
12 | 128baa177046a4 |
13 | 584c01c7c69cc |
14 | 2468d417aa228 |
15 | 1030bbe0b3e37 |
hex | 779abf6e62dc |
131506520351452 has 12 divisors (see below), whose sum is σ = 235488420164536. Its totient is φ = 64224114590160.
The previous prime is 131506520351443. The next prime is 131506520351573. The reversal of 131506520351452 is 254153025605131.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a junction number, because it is equal to n+sod(n) for n = 131506520351399 and 131506520351408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382286396199 + ... + 382286396542.
Almost surely, 2131506520351452 is an apocalyptic number.
It is an amenable number.
131506520351452 is a deficient number, since it is larger than the sum of its proper divisors (103981899813084).
131506520351452 is a wasteful number, since it uses less digits than its factorization.
131506520351452 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 764572792788 (or 764572792786 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 43.
Adding to 131506520351452 its reverse (254153025605131), we get a palindrome (385659545956583).
The spelling of 131506520351452 in words is "one hundred thirty-one trillion, five hundred six billion, five hundred twenty million, three hundred fifty-one thousand, four hundred fifty-two".
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