Base | Representation |
---|---|
bin | 111101001111001110… |
… | …1110100000010001101 |
3 | 110120102222211000002212 |
4 | 1322132131310002031 |
5 | 4123311423244232 |
6 | 140225213000205 |
7 | 12333611306453 |
oct | 1723635640215 |
9 | 416388730085 |
10 | 131507634317 |
11 | 508546a4104 |
12 | 215a1783065 |
13 | c52a33a947 |
14 | 65177d89d3 |
15 | 364a3b9eb2 |
hex | 1e9e77408d |
131507634317 has 2 divisors, whose sum is σ = 131507634318. Its totient is φ = 131507634316.
The previous prime is 131507634299. The next prime is 131507634337. The reversal of 131507634317 is 713436705131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83436633316 + 48071001001 = 288854^2 + 219251^2 .
It is a cyclic number.
It is not a de Polignac number, because 131507634317 - 28 = 131507634061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131507634337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65753817158 + 65753817159.
It is an arithmetic number, because the mean of its divisors is an integer number (65753817159).
Almost surely, 2131507634317 is an apocalyptic number.
It is an amenable number.
131507634317 is a deficient number, since it is larger than the sum of its proper divisors (1).
131507634317 is an equidigital number, since it uses as much as digits as its factorization.
131507634317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 158760, while the sum is 41.
It can be divided in two parts, 13150 and 7634317, that added together give a palindrome (7647467).
The spelling of 131507634317 in words is "one hundred thirty-one billion, five hundred seven million, six hundred thirty-four thousand, three hundred seventeen".
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