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1315109105957 is a prime number
BaseRepresentation
bin10011001000110010100…
…111000111000100100101
311122201112012210120011002
4103020302213013010211
5133021320412342312
62444053000123045
7164004425650103
oct23106247070445
94581465716132
101315109105957
11467809895119
12192a63466485
139702542491a
144791a090c73
15243205dc4c2
hex132329c7125

1315109105957 has 2 divisors, whose sum is σ = 1315109105958. Its totient is φ = 1315109105956.

The previous prime is 1315109105951. The next prime is 1315109106007. The reversal of 1315109105957 is 7595019015131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1293346660516 + 21762445441 = 1137254^2 + 147521^2 .

It is an emirp because it is prime and its reverse (7595019015131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1315109105957 - 218 = 1315108843813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315109105951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657554552978 + 657554552979.

It is an arithmetic number, because the mean of its divisors is an integer number (657554552979).

Almost surely, 21315109105957 is an apocalyptic number.

It is an amenable number.

1315109105957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315109105957 is an equidigital number, since it uses as much as digits as its factorization.

1315109105957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 212625, while the sum is 47.

The spelling of 1315109105957 in words is "one trillion, three hundred fifteen billion, one hundred nine million, one hundred five thousand, nine hundred fifty-seven".