Base | Representation |
---|---|
bin | 111101001111010111… |
… | …0101011001101001001 |
3 | 110120110022010120121002 |
4 | 1322132232223031021 |
5 | 4123314041221401 |
6 | 140225451424345 |
7 | 12333664006544 |
oct | 1723656531511 |
9 | 416408116532 |
10 | 131512054601 |
11 | 50857143134 |
12 | 215a31550b5 |
13 | c52b2278b5 |
14 | 651822985b |
15 | 364a98ea6b |
hex | 1e9ebab349 |
131512054601 has 2 divisors, whose sum is σ = 131512054602. Its totient is φ = 131512054600.
The previous prime is 131512054579. The next prime is 131512054607. The reversal of 131512054601 is 106450215131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116444737600 + 15067317001 = 341240^2 + 122749^2 .
It is a cyclic number.
It is not a de Polignac number, because 131512054601 - 210 = 131512053577 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (131512054607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756027300 + 65756027301.
It is an arithmetic number, because the mean of its divisors is an integer number (65756027301).
Almost surely, 2131512054601 is an apocalyptic number.
It is an amenable number.
131512054601 is a deficient number, since it is larger than the sum of its proper divisors (1).
131512054601 is an equidigital number, since it uses as much as digits as its factorization.
131512054601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 131512054601 its reverse (106450215131), we get a palindrome (237962269732).
The spelling of 131512054601 in words is "one hundred thirty-one billion, five hundred twelve million, fifty-four thousand, six hundred one".
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