Base | Representation |
---|---|
bin | 111101001111010111… |
… | …0101011001101001111 |
3 | 110120110022010120121022 |
4 | 1322132232223031033 |
5 | 4123314041221412 |
6 | 140225451424355 |
7 | 12333664006553 |
oct | 1723656531517 |
9 | 416408116538 |
10 | 131512054607 |
11 | 5085714313a |
12 | 215a31550bb |
13 | c52b2278bb |
14 | 6518229863 |
15 | 364a98ea72 |
hex | 1e9ebab34f |
131512054607 has 2 divisors, whose sum is σ = 131512054608. Its totient is φ = 131512054606.
The previous prime is 131512054601. The next prime is 131512054697. The reversal of 131512054607 is 706450215131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131512054607 - 28 = 131512054351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131512054601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756027303 + 65756027304.
It is an arithmetic number, because the mean of its divisors is an integer number (65756027304).
Almost surely, 2131512054607 is an apocalyptic number.
131512054607 is a deficient number, since it is larger than the sum of its proper divisors (1).
131512054607 is an equidigital number, since it uses as much as digits as its factorization.
131512054607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 35.
Adding to 131512054607 its reverse (706450215131), we get a palindrome (837962269738).
The spelling of 131512054607 in words is "one hundred thirty-one billion, five hundred twelve million, fifty-four thousand, six hundred seven".
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