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131513547103 = 196921765637
BaseRepresentation
bin111101001111011010…
…0010111100101011111
3110120110101221101220221
41322132310113211133
54123314432001403
6140225543422211
712334012464061
oct1723664274537
9416411841827
10131513547103
1150857a72504
12215a3754967
13c52b62b033
1465184d7731
15364ab86dbd
hex1e9ed1795f

131513547103 has 4 divisors (see below), whose sum is σ = 138435312760. Its totient is φ = 124591781448.

The previous prime is 131513547079. The next prime is 131513547149. The reversal of 131513547103 is 301745315131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131513547103 - 225 = 131479992671 is a prime.

It is a super-2 number, since 2×1315135471032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131513547203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3460882800 + ... + 3460882837.

It is an arithmetic number, because the mean of its divisors is an integer number (34608828190).

Almost surely, 2131513547103 is an apocalyptic number.

131513547103 is a deficient number, since it is larger than the sum of its proper divisors (6921765657).

131513547103 is an equidigital number, since it uses as much as digits as its factorization.

131513547103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6921765656.

The product of its (nonzero) digits is 18900, while the sum is 34.

The spelling of 131513547103 in words is "one hundred thirty-one billion, five hundred thirteen million, five hundred forty-seven thousand, one hundred three".

Divisors: 1 19 6921765637 131513547103