Base | Representation |
---|---|
bin | 111101001111011101… |
… | …0111001110011000111 |
3 | 110120110112011102201101 |
4 | 1322132322321303013 |
5 | 4123320401310403 |
6 | 140230044240531 |
7 | 12334033160203 |
oct | 1723672716307 |
9 | 416415142641 |
10 | 131515260103 |
11 | 50858a32507 |
12 | 215a4240147 |
13 | c52baaa946 |
14 | 6518821b03 |
15 | 364adc471d |
hex | 1e9eeb9cc7 |
131515260103 has 4 divisors (see below), whose sum is σ = 134573754568. Its totient is φ = 128456765640.
The previous prime is 131515260089. The next prime is 131515260109. The reversal of 131515260103 is 301062515131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131515260103 is a prime.
It is a super-3 number, since 3×1315152601033 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131515260109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1529247168 + ... + 1529247253.
It is an arithmetic number, because the mean of its divisors is an integer number (33643438642).
Almost surely, 2131515260103 is an apocalyptic number.
131515260103 is a deficient number, since it is larger than the sum of its proper divisors (3058494465).
131515260103 is an equidigital number, since it uses as much as digits as its factorization.
131515260103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3058494464.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 131515260103 its reverse (301062515131), we get a palindrome (432577775234).
The spelling of 131515260103 in words is "one hundred thirty-one billion, five hundred fifteen million, two hundred sixty thousand, one hundred three".
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